120
Are the last two digits divisible by 4
Are the last three digits divisble by 8
Are the sum of the digits divisible by 9
1048
Are the last three digits divisible by 8
20/4 = ?
120/8 = ?
3/9 = ?
48/8 = ?
yes all of these are right.
i really don't know the answer, but i assume its A
To determine if the last two digits of a number are divisible by 4, you need to check if the number formed by the last two digits is divisible by 4.
In the case of the number 120, the last two digits are "20". To check if "20" is divisible by 4, you need to see if it is a multiple of 4. Since 20 is indeed a multiple of 4, then the last two digits of 120 are divisible by 4.
To determine if the last three digits of a number are divisible by 8, you need to check if the number formed by the last three digits is divisible by 8.
In the case of the number 120, the last three digits are "120". To check if "120" is divisible by 8, you need to see if it is a multiple of 8. Since 120 is not a multiple of 8, then the last three digits of 120 are not divisible by 8.
To determine if the sum of the digits of a number is divisible by 9, you need to find the sum of all the individual digits of the number and check if that sum is divisible by 9.
In the case of the number 120, the sum of the digits is 1 + 2 + 0 = 3. The sum of the digits is not divisible by 9 (since 3 ÷ 9 = 0 with a remainder of 3), so the sum of the digits of 120 is not divisible by 9.
For the number 1048, to determine if the last three digits are divisible by 8, you need to check if the number formed by the last three digits is divisible by 8.
In this case, the last three digits are "048". To check if "048" is divisible by 8, you need to see if it is a multiple of 8. Since 48 is a multiple of 8 (48 ÷ 8 = 6), then the last three digits of 1048 are divisible by 8.