A bicycle of mass 14.6 kg and a rider of mass 50kg generate a net force of 12N.How fast are they going after 2.0 seconds?

To calculate the speed of the bicycle and the rider after 2.0 seconds, you need to use Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration.

First, let's calculate the total mass of the system by adding the mass of the bicycle and the mass of the rider:
Total mass = mass of bicycle + mass of rider
Total mass = 14.6 kg + 50 kg
Total mass = 64.6 kg

Next, we'll calculate the acceleration of the system using Newton's second law:
net force = mass × acceleration
12 N = 64.6 kg × acceleration

Now, we can solve for acceleration:
acceleration = 12 N / 64.6 kg
acceleration ≈ 0.185 m/s²

To calculate the final speed of the bicycle and the rider after 2.0 seconds, we can use the kinematic equation:
final velocity = initial velocity + (acceleration × time)

Assuming the initial velocity is 0 m/s since it is not given in the question, we have:
final velocity = 0 m/s + (0.185 m/s² × 2.0 s)
final velocity = 0.37 m/s

Therefore, after 2.0 seconds, the bicycle and the rider will be moving at a speed of approximately 0.37 m/s.