How do you find the axis of symmetry for this problem:
-2(x+2)^2-1
did you mean the parabola
y = -2(x+2)^2 - 1 ?
Can you tell me what the vertex is?
Doesn't the axis of symmetry run vertically through the vertex?
-2(x+2)^2-1
y = -2(x+2)^2 - 1 ?
Can you tell me what the vertex is?
Doesn't the axis of symmetry run vertically through the vertex?