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C7H6O3+CH3OH→C8H8O3+H2O
In any experiment, 1.50g of salicyclic acid is reacted with 11.20g of methanol. The yield of methyl salicylate, C8H8O3, is 1.31g. What is the percent yield?

percent is 77.l1%

is this correct?

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asked by Molly
  1. theoretical yield= 1.50/molmassC7H6O3 * molmassC8H8OH

    =1.50/138.12 * 152.14=1.65g

    percent yield= 1.31/1.65=.792
    check my calcs.

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