The value of a "Mint State-63" 1950 Jefferson nickel minted at Denver is 8/7 the value of a 1945 nickel at Philadelphia. Together, the total value of the two coins is $15. What is the value of each coin?
let the value of the '45 nickel be $x
then the Jefferson nickel is worth (8/7)x
x + 8x/7 = 15
7x + 8x = 105
15x = 105
x = 7
take it from there.
Thank you so much Reiny.
To solve this problem, let's assign variables to the values of the two coins. Let's say that the value of the 1945 nickel at Philadelphia is x dollars. Therefore, the value of the 1950 Jefferson nickel at Denver would be (8/7) * x dollars.
According to the problem, the total value of the two coins is $15. So we can set up the equation:
x + (8/7) * x = 15
To solve for x, we can simplify the equation:
(15/7) * x = 15
Now, we can divide both sides of the equation by (15/7) to isolate x:
x = 15 / (15/7)
x = 15 * (7/15)
x = 7
Therefore, the value of the 1945 nickel at Philadelphia is $7.
To find the value of the 1950 Jefferson nickel at Denver, we can substitute the value of x into our equation: (8/7) * 7
Value of the 1950 Jefferson nickel = (8/7) * 7 = 8
Therefore, the value of the 1950 Jefferson nickel at Denver is $8.
To summarize:
Value of the 1945 nickel at Philadelphia = $7
Value of the 1950 Jefferson nickel at Denver = $8