How many calories are absorbed by a sample of water with a mass of 500 grams as it changes from 50°C to 56°C? The specific heat capacity of water is 1.00 cal/g°C.
To calculate the amount of calories absorbed by the water as it changes temperature, you can use the formula:
Q = mcΔT
Where:
Q represents the amount of heat gained or lost by a substance (in this case, the water)
m represents the mass of the water (500 grams)
c represents the specific heat capacity of water (1.00 cal/g°C)
ΔT represents the change in temperature (56°C - 50°C = 6°C)
Plugging in the values:
Q = (500 g) * (1.00 cal/g°C) * (6°C)
Q = 3000 cal
Therefore, the water absorbs 3000 calories of heat as it changes from 50°C to 56°C.