when water is added to solid calcium carbide, CaC2, acetylene gas, C2H2, and calcium hydroxide, Ca(OH)2 are produced.
how many moles of acetylene are produced when 0.50 mole of calcium carbide reacts?
can anyone explain this to me please
First question answered below.
Second question: Look at the coefficients in the balanced equation. They tell you the ratio of the products to reactants and to each other.
Sure! I'd be happy to explain.
To determine the number of moles of acetylene gas produced when 0.50 moles of calcium carbide reacts, we can use the balanced chemical equation for the reaction between calcium carbide and water.
The balanced chemical equation is as follows:
CaC2 + 2H2O → C2H2 + Ca(OH)2
From this equation, we can see that for every 1 mole of calcium carbide (CaC2) that reacts, 1 mole of acetylene gas (C2H2) is produced.
Therefore, since we have 0.50 moles of calcium carbide, we would also expect to have 0.50 moles of acetylene gas produced.
So, the answer is: 0.50 moles of acetylene gas are produced when 0.50 moles of calcium carbide react.
I hope this explanation helps! Let me know if you have any further questions.