A fisherman notices that his boat is moving up and down periodically, owing to waves on the surface of the water. It takes a time of 2.70 s for the boat to travel from its highest point to its lowest, a total distance of 0.700 m. The fisherman sees that the wave crests are spaced a horizontal distance of 6.50 m apart.How fast are the waves traveling? What is the amplitude A of each wave?
The amplitude A is half the distance from highest to lowest elevation, or 0.350 m.
The period of the wave motion is 2.7 x 2 = 5.40 s
The wavelength is L = 6.50 m
Wave speed V = (wavelength)/(period)
= 6.5/5.4 = ___ m/s
You are given half period as 2.7sec. You are given wavelength of 6.50m.
Amplitude is given as .7/2
speed= wavelength*1/period
yup Drwls is right, the answer is 1.13 m/s
drwls knows his stuff
To determine the speed of the waves, we need to use the formula:
Wave speed = Distance / Time
Given that the distance between wave crests is 6.50 m and the time it takes for the boat to travel from the highest to the lowest point is 2.70 s, we can calculate the wave speed:
Wave speed = 6.50 m / 2.70 s
Wave speed ≈ 2.41 m/s
Therefore, the waves are traveling at a speed of approximately 2.41 m/s.
To find the amplitude A of each wave, we can use the formula:
Amplitude = Distance / 2
Given that the total distance traveled by the boat from the highest to the lowest point is 0.700 m, we can calculate the amplitude:
Amplitude = 0.700 m / 2
Amplitude = 0.350 m
Hence, the amplitude of each wave is 0.350 m.