C7H6O3+CH3OH→C8H8O3+H2O
In any experiment, 1.50g of salicyclic acid is reacted with 11.20g of methanol. The yield of methyl salicylate, C8H8O3, is 1.31g. What is the percent yield?
To calculate the percent yield, we need to compare the actual yield (1.31g) to the theoretical yield. The theoretical yield is the amount of product that would be obtained if the reaction proceeded perfectly.
Let's start by determining the molar masses of the reactants and products involved in the reaction:
Molar mass of salicylic acid (C7H6O3):
C = 12.01 g/mol
H = 1.008 g/mol
O = 16.00 g/mol
Molar mass = (7 * 12.01 g/mol) + (6 * 1.008 g/mol) + (3 * 16.00 g/mol) = 138.12 g/mol
Molar mass of methanol (CH3OH):
C = 12.01 g/mol
H = 1.008 g/mol
O = 16.00 g/mol
Molar mass = 12.01 g/mol + (4 * 1.008 g/mol) + 16.00 g/mol = 32.04 g/mol
Molar mass of methyl salicylate (C8H8O3):
C = 12.01 g/mol
H = 1.008 g/mol
O = 16.00 g/mol
Molar mass = (8 * 12.01 g/mol) + (8 * 1.008 g/mol) + (3 * 16.00 g/mol) = 152.16 g/mol
Next, we need to determine the moles of salicylic acid and methanol used in the reaction:
Moles of salicylic acid = mass / molar mass
= 1.50 g / 138.12 g/mol = 0.0109 mol
Moles of methanol = mass / molar mass
= 11.20 g / 32.04 g/mol = 0.349 mol
The balanced equation tells us that the ratio of moles of salicylic acid to moles of methyl salicylate is 1:1. Therefore, the theoretical yield of methyl salicylate is also 0.0109 mol.
Now, we can calculate the theoretical yield in grams:
Theoretical yield = moles of product * molar mass
= 0.0109 mol * 152.16 g/mol = 1.66 g
Finally, we can calculate the percent yield:
Percent yield = (actual yield / theoretical yield) * 100
= (1.31 g / 1.66 g) * 100
= 79.04%
Therefore, the percent yield of methyl salicylate is approximately 79.04%.
1. Writ and balance the equation.
2. Convert 11.2 g methanol to moles. moles = grams/molar mass.
3. Using the coefficients in the balanced equation, convert moles methanol to moles of the product.
4. Now convert moles of the product to grams. g = moles x molar mass. This is the theoretical yield.
5. %yield = (actual yield/theoretical yield)*100 = ??
From my understanding the equation is already balanced, correct?
My answer: 26.7%, is this correct?
Work: (11.20gCH3OH)(1 mol CH3OH)/32.05gCH3OH=0.3495gCH3OH
0.3495g/1.31g= 26.68%
To determine the percent yield, you need to compare the actual yield (1.31g) with the theoretical yield. The theoretical yield is the maximum amount of product that can be obtained based on stoichiometry.
First, you need to calculate the molar masses of salicylic acid (C7H6O3), methanol (CH3OH), and methyl salicylate (C8H8O3).
- Molar mass of salicylic acid (C7H6O3):
(12.01 g/mol x 7) + (1.01 g/mol x 6) + (16.00 g/mol x 3) = 138.12 g/mol
- Molar mass of methanol (CH3OH):
(12.01 g/mol x 1) + (1.01 g/mol x 4) + (16.00 g/mol x 1) = 32.04 g/mol
- Molar mass of methyl salicylate (C8H8O3):
(12.01 g/mol x 8) + (1.01 g/mol x 8) + (16.00 g/mol x 3) = 152.15 g/mol
Next, determine the number of moles of salicylic acid and methanol used in the reaction:
- Moles of salicylic acid = mass (in grams) / molar mass
Moles of salicylic acid = 1.50 g / 138.12 g/mol
- Moles of methanol = mass (in grams) / molar mass
Moles of methanol = 11.20 g / 32.04 g/mol
Now, you need to determine the ratio between the reactants and products based on the balanced chemical equation:
C7H6O3 + CH3OH → C8H8O3 + H2O
From the equation, you can see that the ratio between salicylic acid and methyl salicylate is 1:1.
Therefore, the number of moles of methyl salicylate produced would be the same as the number of moles of salicylic acid used.
Now, calculate the theoretical yield of methyl salicylate:
- Theoretical yield (in grams) = moles of salicylic acid x molar mass of methyl salicylate
Theoretical yield = Moles of salicylic acid x 152.15 g/mol
Finally, calculate the percent yield:
Percent yield = (Actual yield / Theoretical yield) x 100%
Percent yield = (1.31 g / Theoretical yield) x 100%