Calculate the total quantity of heat required to convert 25.0 g of liquid CCl4(l) from 25.0°C to gaseous CCl4 at 76.8°C (the normal boiling point for CCl4)? The specific heat of CCl4(l) is its heat of fusion is and its heat of vaporization is

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  1. q1 = heat to move CCl4 liquid to its boiling point.
    q1 = mass CCl4 x specific heat x (Tfinal-Tinitial).
    q2 = meat to vaporize liquid CCl4 to vapor at 76.8 C.
    q2 = mass x heat vaporization.

    total heat = q1 + q2.

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  2. When you calculate it, the answer should be 5.74kj

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