Calculate the total quantity of heat required to convert 25.0 g of liquid CCl4(l) from 25.0°C to gaseous CCl4 at 76.8°C (the normal boiling point for CCl4)? The specific heat of CCl4(l) is its heat of fusion is and its heat of vaporization is
I like trains
q1 = heat to move CCl4 liquid to its boiling point.
q1 = mass CCl4 x specific heat x (Tfinal-Tinitial).
q2 = meat to vaporize liquid CCl4 to vapor at 76.8 C.
q2 = mass x heat vaporization.
total heat = q1 + q2.
When you calculate it, the answer should be 5.74kj
dosas
Well, well, well, looks like we have a hot chemistry problem here! Let's heat things up, shall we?
To solve this question, we need to consider two steps: heating the liquid CCl4 from 25.0°C to the boiling point, and then vaporizing it. Let's get crackin'!
Step 1: Heating the Liquid CCl4
To calculate the heat required to raise the temperature of the liquid CCl4, we use the formula:
Q = mcΔT
Where:
Q = energy (heat) required
m = mass of the substance
c = specific heat capacity of the substance
ΔT = change in temperature
Given:
m = 25.0 g
c = specific heat of CCl4(l) (but you didn't provide it, so I can't use my clever jokes about it)
ΔT = difference in temperature = 76.8°C - 25.0°C = 51.8°C
Now I would love to calculate this for you, but I don't have the specific heat capacity of CCl4(l). So, I'm sorry to disappoint, but this clown can't finish the calculation without that specific information.
However, if you provide the specific heat capacity, feel free to ask again, and I'll be happy to oblige with a hilarious calculation!
To calculate the total quantity of heat required to convert CCl4 from a liquid to a gas, we need to consider the following steps:
1. Heating the liquid CCl4 from 25.0°C to its boiling point.
2. Vaporizing the liquid CCl4 at its boiling point to form a gas.
Let's break down each step and calculate the heat energy involved.
Step 1: Heating the liquid CCl4 from 25.0°C to its boiling point.
To calculate the heat energy for this step, we use the equation:
Q1 = m × C × ΔT
Where:
Q1 is the heat energy required (in joules),
m is the mass of the substance (in grams),
C is the specific heat capacity of the substance (in J/g°C), and
ΔT is the change in temperature (in °C).
Given:
m = 25.0 g (mass of CCl4)
C = specific heat of CCl4(l) (you did not provide this value)
ΔT = (76.8°C - 25.0°C) = 51.8°C
Since you did not provide the specific heat capacity of CCl4(l), please provide that information, and we will resume the calculation from there.