We want to prepare 150 mL of 1.0 M HA solution by diluting the stock 8.7 M HA solution with water. What volume of 8.7 M HA solution is needed?
mL x M = mL x M is the dilution formula.
To prepare 150 mL of 1.0 M HA solution, we will need to dilute the stock 8.7 M HA solution with water.
The formula for dilution is:
C1V1 = C2V2
Where:
C1 = initial concentration of the stock solution
V1 = volume of the stock solution to be used
C2 = final concentration of the diluted solution
V2 = final volume of the diluted solution
In this case:
C1 = 8.7 M (concentration of the stock solution)
V1 = volume of the stock solution to be used (unknown)
C2 = 1.0 M (desired final concentration)
V2 = 150 mL (final volume of the diluted solution)
Using the formula, we can calculate the volume of the stock solution needed:
(8.7 M)(V1) = (1.0 M)(150 mL)
Now, let's solve for V1:
V1 = (1.0 M)(150 mL) / 8.7 M
V1 = (1.0 * 150) / 8.7
V1 ≈ 17.24 mL
Therefore, you will need approximately 17.24 mL of the 8.7 M HA solution to prepare 150 mL of 1.0 M HA solution by dilution with water.
To determine the volume of 8.7 M HA solution needed to prepare 150 mL of 1.0 M HA solution, we can use the equation for dilution:
C1V1 = C2V2
Where:
C1 = initial concentration of the stock solution (8.7 M)
V1 = volume of the stock solution to be used (unknown)
C2 = final concentration of the diluted solution (1.0 M)
V2 = final volume of the diluted solution (150 mL)
We can rearrange the equation and solve for V1:
V1 = (C2 * V2) / C1
Substituting the given values:
V1 = (1.0 M * 150 mL) / 8.7 M
V1 ≈ 17.2 mL
Therefore, approximately 17.2 mL of the 8.7 M HA solution is needed to prepare 150 mL of 1.0 M HA solution.