How fast does water flow from a hole at the bottom of a very wide, 3.7 m deep storage tank filled with water? Ignore viscosity.

The speed of the water leaving is

V = sqrt(2*g*H)
= 8.5 m/s

H is the height of the water above the hole. The same formula applies if the hole is in a side wall.

Oh, trying to make a quick getaway, huh? Alright, let's solve this water problem. Now, if we disregard viscosity, we can assume the water will flow pretty fast, like a speedy gazelle escaping a hungry lion.

To calculate the speed, we can use Torricelli's law, which states that the speed of fluid flowing out of an opening is directly related to the height of the fluid column. In this case, the height of the water column is 3.7 meters.

Now, let's assume the hole is tiny, like a pinprick, and neglect any losses due to friction. With these assumptions, the water will burst out of the hole with gusto!

So, the speed of the water flowing out of the hole will be approximately equal to the speed it would gain if you dropped it from a height of 3.7 meters. And that, my friend, is about 34.34 meters per second! That's as fast as a cheetah chasing its dinner!

But remember, this is all assuming ideal conditions. In reality, factors like viscosity and friction will slow down the flow. So don't go testing this out with a real tank!

To calculate the speed at which water flows from a hole at the bottom of a storage tank, we can use Torricelli's law. This law states that the velocity of water flowing out of an opening at the bottom of a tank can be determined using the equation:

v = √(2gh)

Where:
v is the velocity of the water flow,
g is the acceleration due to gravity (9.8 m/s²),
and h is the height of the water column above the hole.

In this case, the height of the water column is the depth of the storage tank, which is 3.7 m.

Plugging these values into the equation, we get:

v = √(2 * 9.8 * 3.7)
v = √(72.52)
v ≈ 8.51 m/s

Therefore, the water flows out of the hole at a speed of approximately 8.51 meters per second.

To determine the speed at which water flows from a hole at the bottom of a storage tank, we can use Torricelli's Law, also known as the Torricellian equation. This equation relates the velocity of a fluid flowing from an opening to the height of the fluid above the opening.

The equation is as follows:

(v = sqrt(2gh))

Where:
v = velocity of the fluid coming out of the hole
g = acceleration due to gravity (approximately 9.8 m/s²)
h = height of the fluid above the hole

In this case, the height of the fluid above the hole is equal to the depth of the tank, which is 3.7 m.

Plugging in the values into the equation:

v = sqrt(2 * 9.8 * 3.7)
v = sqrt(72.68)
v ≈ 8.53 m/s

Therefore, the water will flow from the hole at a speed of approximately 8.53 m/s.