Given a sufficient supply of nitrogen gas, how many moles of ammonia gas will be produced from 10.8 moles of hydrogen gas?
First you write an equation, then balance it.
N2 + 3H2 ==> 2NH3
10.8 moles H2 x (2 moles NH3/3 moles H2) = mols NH3.
Note that the fraction I used converts moles of one thing into moles of another. Second thing to notice is that the numbers in the fraction are the same as the coefficients in the balanced equation. Third thing to notice is that the denominator of the fraction cancels the numerator of what I started with. Finally, the numerator of the fraction is the unit of the material I want to keep.
HAHAHA thank you!
The answer is 7.2 NH3
To determine the number of moles of ammonia gas produced from a given number of moles of hydrogen gas, you need to use the balanced chemical equation for the reaction between hydrogen gas (H2) and nitrogen gas (N2) to produce ammonia gas (NH3). The balanced equation is:
N2 + 3H2 -> 2NH3
According to the balanced equation, it takes three moles of hydrogen gas to produce two moles of ammonia gas. Therefore, the molar ratio between hydrogen gas and ammonia gas is 3:2.
To determine the number of moles of ammonia gas produced, you can use the following conversion:
moles of ammonia gas = (moles of hydrogen gas / molar ratio) * molar ratio of ammonia gas
Given that you have 10.8 moles of hydrogen gas, you can substitute this value into the equation:
moles of ammonia gas = (10.8 moles / 3) * 2
Simplifying the equation:
moles of ammonia gas = 3.6 * 2
moles of ammonia gas = 7.2 moles
Therefore, with a sufficient supply of nitrogen gas, 10.8 moles of hydrogen gas will produce 7.2 moles of ammonia gas.