solve x-2y=2 and 2x-4y=3
then graph each equation
I would use substitution
change the first to
x = 2y + 2
and sub that into the second.
once you get y, sub that back into x = 2y+2
We cannot graph it for you in this format.
when you solve for the equation, you can easily graph. for example lets say the equation you got is y=3x+3 (i just made it up. not the answer to your problem)
What this equation says is if you know X, you can multiply by 3 and then add 3 and you will get the Y value. So just plug in zero,one,two,three and negative 1,2,3 and you will get the basic idea of the shape. If you plug in zero for x, y would be 3. So you would put a point at (0,3).
To solve the system of equations x - 2y = 2 and 2x - 4y = 3, we can use either the substitution method or the elimination method. Let's use the elimination method to find the solution.
1. Multiply both sides of the second equation, 2x - 4y = 3, by -1 to make the coefficients of x in both equations equal:
-2x + 4y = -3
2. Add the two equations together to eliminate x:
(x - 2y) + (-2x + 4y) = 2 + (-3)
-2y + 4y = -1
2y = -1
3. Solve for y by dividing both sides of the equation by 2:
y = -1/2
4. Substitute the value of y back into either of the original equations to find the value of x:
x - 2(-1/2) = 2
x + 1 = 2
x = 1
Therefore, the solution to the system of equations is x = 1 and y = -1/2.
To graph each equation, let's represent them as linear functions and plot them on a coordinate plane:
First equation: x - 2y = 2
Rearrange the equation to slope-intercept form (y = mx + b):
-2y = -x + 2
y = (1/2)x - 1
Second equation: 2x - 4y = 3
Rearrange the equation to slope-intercept form (y = mx + b):
-4y = -2x + 3
y = (1/2)x - 3/4
Now we can plot these two lines on a graph to see how they intersect and find the point of solution (1, -1/2).