Calculate the grams of HNO3 in 35.0 ml of a 6.00 M HNO3 solution

Mols HNO3 in 1 L = 6.00

moles HNO3 in 35 mL = 6.00 x (35.0/1000) = ??
grams = moles x molar mass = ??

To calculate the grams of HNO3 in 35.0 ml of a 6.00 M HNO3 solution, you can use the formula:

moles = concentration * volume

First, convert the volume from milliliters (ml) to liters (L) by dividing it by 1000:

35.0 ml รท 1000 = 0.035 L

Next, substitute the values into the formula:

moles = 6.00 M * 0.035 L

Calculate the moles of HNO3 in the solution:

moles = 0.21 mol

To find the grams of HNO3, you need to multiply the moles of HNO3 by its molar mass. The molar mass of HNO3 can be calculated as follows:

H = 1.01 g/mol
N = 14.01 g/mol
O = 16.00 g/mol (x3 as there are three oxygen atoms)

Molar mass of HNO3 = 1.01 g/mol + 14.01 g/mol + (16.00 g/mol * 3) = 63.01 g/mol

Finally, calculate the grams of HNO3:

grams = moles * molar mass
grams = 0.21 mol * 63.01 g/mol

grams = 13.23 g

Therefore, there are 13.23 grams of HNO3 in 35.0 ml of a 6.00 M HNO3 solution.