Identify the balanced net ionic equation for the reaction
2Na3PO4(aq) + 3CaCl2(aq)�¨ 6NaCl(aq) + Ca3(PO4)2(s)
To identify the balanced net ionic equation for the given reaction, we need to first write the molecular equation and then break it down into ionic species. Finally, we cancel out the spectator ions to get the net ionic equation. Here's the step-by-step process:
Step 1: Write the molecular equation:
2Na3PO4(aq) + 3CaCl2(aq) → 6NaCl(aq) + Ca3(PO4)2(s)
Step 2: Split the soluble ionic compounds into their respective ions:
2Na3PO4(aq) → 6Na+(aq) + 2PO4^3-(aq)
3CaCl2(aq) → 6Ca2+(aq) + 6Cl^-(aq)
6NaCl(aq) → 6Na+(aq) + 6Cl^-(aq)
Step 3: Write the balanced net ionic equation by canceling out the spectator ions:
Canceling out the Na+(aq) and Cl^-(aq) ions on both sides of the reaction, we get the net ionic equation:
2PO4^3-(aq) + 3Ca2+(aq) → Ca3(PO4)2(s)
Therefore, the balanced net ionic equation for the given reaction is:
2PO4^3-(aq) + 3Ca2+(aq) → Ca3(PO4)2(s)