If a 31.0 N·m torque on a wheel causes angular acceleration 22.0 rad/s2, what is the wheel's rotational inertia?
To find the wheel's rotational inertia, we can use the equation:
τ = Iα
Where:
τ is the torque applied to the wheel (31.0 N·m)
I is the rotational inertia of the wheel (unknown)
α is the angular acceleration of the wheel (22.0 rad/s^2)
To solve for I, we need to rearrange the equation:
I = τ / α
Now we can substitute the given values into the equation:
I = 31.0 N·m / 22.0 rad/s^2
Calculating this:
I = 1.41 kg·m^2
Therefore, the wheel's rotational inertia is 1.41 kg·m^2.