some ordered pairs for a linear function of x are given in the table below.

x y
1 1
3 7
5 13
7 19

sorry im not good at tables

which of the following equations was used too generaTE the table above

a y=2x+1
b y=2x-1
c y=3x-2
d y=4x-3

To determine which equation was used to generate the table, we can look at the pattern in the y-values for each x-value.

Looking at the table, we see that as x increases by 2, y increases by 6. This means that the rate of change, or slope, between any two consecutive points is constant and equal to 6/2 = 3.

Let's check each equation to see which one matches this pattern:

a) y = 2x + 1: This equation has a slope of 2, which does not match the pattern in the table.

b) y = 2x - 1: This equation has a slope of 2, which also does not match the pattern.

c) y = 3x - 2: This equation has a slope of 3, which matches the pattern in the table.

d) y = 4x - 3: This equation has a slope of 4, which does not match the pattern.

Therefore, the equation that was used to generate the table above is y = 3x - 2.

To determine the equation used to generate the table, we need to look for a consistent pattern in the given ordered pairs. One approach is to calculate the slope (m) and the y-intercept (b) using two of the ordered pairs.

Let's choose the first two ordered pairs (1, 1) and (3, 7):

Slope (m) = (change in y) / (change in x) = (7 - 1) / (3 - 1) = 6 / 2 = 3

Now that we have the slope, we can use the point-slope form of a linear equation to determine the y-intercept:
y - y1 = m(x - x1)

Using the point (1, 1) and slope (m = 3):
y - 1 = 3(x - 1)
y - 1 = 3x - 3

Simplifying the equation, we get:
y = 3x - 2

Comparing this equation to the given options:
a) y = 2x + 1
b) y = 2x - 1
c) y = 3x - 2 -> Matches the equation we derived
d) y = 4x - 3

Therefore, the equation used to generate the given table is y = 3x - 2. So the correct answer is option c.

you plug/ substitute x and y in each equation

start with A first
x=1 y=1 1=(2x1)+1= 3 so not same
x=1 y=7 7=(2x3)-1=5
x=5 y=13 13=(3x5)-13=2
x=7 y=19 19=(4x7)-3=19 it is the same because y=19 and then the answer you got when you plug in 7 is 19

now A equation
x=1 y=1 1=(2x1)+1=3 not the same
x=3 y=7 7=(2x3)+1=7 same

C
x=5 y=13 c y=13, x= 5 (3x5)-2=13 same

so what is left over is A with x=1 y=1