what is the equation of the line that has a slope of 4 and passes through the piont (3,-10)?
a y=4x-22
b y=4x+22
c y=4x-43
d y=4x+43
y = 4 x + b
-10 = 4*3 + b
-10 = 12 + b
-22 = b
y = 4 x -22
To find the equation of a line given its slope and a point it passes through, we can use the slope-intercept form of a linear equation: y = mx + b, where m represents the slope and b represents the y-intercept.
In this case, the slope is given as 4, and the line passes through the point (3, -10).
To find the y-intercept (b), we can substitute the values of x and y from the given point into the equation and solve for b.
-10 = 4(3) + b
-10 = 12 + b
b = -10 - 12
b = -22
Therefore, the equation of the line with a slope of 4 and passing through the point (3, -10) is y = 4x - 22.
So, the correct option is a) y = 4x - 22.