Assume that a deposit of oil is located 2000 m directly below. Estimate the size of the deposit, assumed spherical.
I feel it is difficult to answer this question because we need more information.
I posted an answer to a different but similar version of this question two days ago.
http://www.jiskha.com/display.cgi?id=1270523096
You do need more information. Are there measurements of the variation in the acceleration of gravity above the deposit?
To estimate the size of the deposit, we need to determine the volume of the sphere it forms.
The formula for the volume of a sphere is given by:
V = (4/3) * π * r^3,
where V is the volume of the sphere and r is the radius of the sphere.
In this case, the deposit is located 2000 m directly below, so the radius of the sphere would be 2000 m.
Let's plug in the values into the formula to calculate the volume of the deposit:
V = (4/3) * π * (2000)^3
≈ 33,509,480,000 π
Now, to obtain a numerical estimate, we can use the approximate value for π, which is 3.14.
Thus, the estimated size of the deposit is:
V ≈ 33,509,480,000 * 3.14
≈ 105,122,199,200 cubic meters
So, the estimated size of the deposit is approximately 105,122,199,200 cubic meters.