If 0.0308 M aqueous FeCl3 is produced stoichiometrically according to the balanced equation in a reaction solution with a total volume of 1200 mL, what mass (g) of gaseous H2S is produced?

Fe2S3(s) + 6HCl(aq) �¨ 3 H2S(g) + 2 FeCl3(aq)

How many moles of ferric chloride do you have? .0308M*1.2L=...

according to the balance equation, how many moles of H2S will you have? 3/2 of moles of ferric chloride.

How many grams is that?