A 2.00L flask is filled with propane gas(C3H8)at 1.00atm and 15C. What is the mass of propane in the flask?
you didnt need to comment if you werent going to help or give the answer. your relpying for no reason. idk the answer sorry.
Well i mean i would know how to do this stuff but, ive been out of school due to heart and brain problems, so my teachers sent me home with work. Im ust trying to get caught up. But thank you for trying to help me.
Yeah like i know what formula to use but im not sure how to plug it all in and stuff, Im so new at this stuff. Please help?
Like i don't know how you know what numbers to plug into the formual.
To calculate the mass of propane in the flask, we need to use the ideal gas law equation. First, let's convert the given temperature from Celsius to Kelvin:
T = 15°C + 273.15 = 288.15 K
Next, we can use the ideal gas law equation, which is:
PV = nRT
Where:
P = pressure in atmospheres (1.00 atm in this case)
V = volume in liters (2.00 L in this case)
n = number of moles of gas
R = ideal gas constant (0.0821 L·atm/(mol·K))
T = temperature in Kelvin (288.15 K in this case)
Rearranging the equation, we can solve for n:
n = (PV) / (RT)
Now substituting the given values, we can calculate the number of moles, n:
n = (1.00 atm * 2.00 L) / (0.0821 L·atm/(mol·K) * 288.15 K)
n ≈ 0.092 mol (rounded to three significant figures)
Next, we need to convert moles of propane to its mass. We can use the molar mass of propane, which is:
C3H8 = (3 * 12.01 g/mol) + (8 * 1.01 g/mol)
C3H8 = 44.10 g/mol (rounded to two decimal places)
Finally, we multiply the number of moles by the molar mass to get the mass of propane in the flask:
mass = n * molar mass
mass = 0.092 mol * 44.10 g/mol
mass ≈ 4.06 g (rounded to three significant figures)
Therefore, the mass of propane in the flask is approximately 4.06 grams.
Use PV=nRT to find the moles, n.
Then convert that to grams.