The value of H° for the reaction below is -482 kJ. Calculate the heat (kJ) released to the surroundings when 12.0 g of CO (g) reacts completely.
No reaction below.
To calculate the heat released to the surroundings when 12.0 g of CO (g) reacts completely, we need to use the equation:
ΔH = q
Where:
ΔH = change in enthalpy
q = heat released
Given:
H° = -482 kJ (the change in enthalpy)
Molar mass of CO = 28.01 g/mol
To find the moles of CO (g) present in 12.0 g, we can use the molar mass:
Moles of CO = Mass of CO / Molar mass of CO
= 12.0 g / 28.01 g/mol
Next, we can use the stoichiometry of the balanced equation to determine the molar ratio between CO and ΔH. The balanced equation for the reaction is:
CO (g) → CO2 (g)
From the equation, we can see that the molar ratio between CO and ΔH is 1:1. This means that for every 1 mole of CO, the ΔH is -482 kJ.
Therefore, the number of moles of CO is equal to the number of moles of ΔH.
Finally, we can calculate the heat released using the equation:
q = ΔH = -482 kJ/mol * (12.0 g / 28.01 g/mol)
Multiplying the moles of CO by the change in enthalpy, we get:
q = -207.19 kJ
Therefore, the heat released to the surroundings when 12.0 g of CO (g) reacts completely is -207.19 kJ.
To calculate the heat released to the surroundings when 12.0 g of CO (g) reacts completely, we need to use the equation:
q = m*C*ΔT
Where:
q is the heat released to the surroundings
m is the mass of the substance (CO in this case) in grams
C is the specific heat capacity of the substance (CO in this case)
ΔT is the change in temperature
But first, let's determine the number of moles of CO (g) present in 12.0 g of CO. We can use the molar mass of CO to do this.
1. Calculate the molar mass of CO, which is the sum of the atomic masses of carbon (C) and oxygen (O). The atomic masses are found on the periodic table.
Molar mass of C = 12.01 g/mol
Molar mass of O = 16.00 g/mol
So, the molar mass of CO is: 12.01 g/mol + 16.00 g/mol = 28.01 g/mol
2. Now, use the molar mass to calculate the number of moles of CO:
Number of moles = Mass of CO / Molar mass of CO
Number of moles = 12.0 g / 28.01 g/mol
3. Calculate ΔH, the enthalpy change for the reaction:
ΔH = H° * Number of moles
ΔH = -482 kJ/mol * (12.0 g / 28.01 g/mol)
4. Finally, calculate q using the equation mentioned above:
q = ΔH
Remember to convert the ΔH value to kJ if necessary.