If two dice are rolled, what is the probability that their sum will be a number greater
than 5 ?
[A]1/6 [B]1/3 [C]13/18 [D]5/6 [E] None of these.
i think it is c am i right?
13/18
so i am right?
What is the probability the sum is 2,3,4 or 5? If you find that and subtract it from 1 you'll have the probability the sum is greater than 5.
The sample space has 36 possible outcomes. There's 1 way to get 2, 2 ways to get 3, 3 ways to get 4 and 4 ways to get a 5. There are 1+2+3+4 outcomes whose sum <=5, or the prob. the sum <=5 is 10/36. So 1 - 10/36 = 26/36 is the probability the sum is greater than 5
So yes, you're right, but I don't know what your reasoning is; be prepared to defend, i.e. explain, your answer.
Yes, you are correct. The probability that the sum of two dice is greater than 5 can be found by subtracting the probability of the sum being 2, 3, 4, or 5 from 1.
To find the probability of getting a sum of 2, 3, 4, or 5, we need to calculate the number of favorable outcomes and divide it by the total number of possible outcomes.
There are 36 possible outcomes when two dice are rolled because each die has 6 possible outcomes (1, 2, 3, 4, 5, or 6).
To find the number of favorable outcomes for a sum of 2, there is only one combination: rolling a 1 on both dice.
For a sum of 3, there are two combinations: rolling a 1 and 2, or rolling a 2 and 1.
Similarly, for a sum of 4, there are three combinations: rolling a 1 and 3, rolling a 3 and 1, or rolling a 2 and 2.
For a sum of 5, there are four combinations: rolling a 1 and 4, rolling a 4 and 1, rolling a 2 and 3, or rolling a 3 and 2.
Therefore, the total number of favorable outcomes for a sum of 2, 3, 4, or 5 is 1 + 2 + 3 + 4 = 10.
The probability of getting a sum of 2, 3, 4, or 5 is 10/36.
To find the probability that the sum is greater than 5, we subtract this probability from 1.
So, 1 - 10/36 = 26/36, which simplifies to 13/18.
Therefore, the probability of the sum of two dice being greater than 5 is 13/18.
You are correct in choosing option C as the answer.