a consultant traveled 7 hours to attend a meeting. The return trip took only 6 hours because the speed was 10 miles per hour faster. What was the consultant's speed each way?
Math question here.
proportions: is the following proportion true or false?
9.375/3=25/8
To find the consultant's speed for each leg of the trip, we'll use the formula:
speed = distance / time.
Let's denote the speed of the initial trip as "x" (in miles per hour).
The distance covered in the initial trip is 7 hours * x mph = 7x miles.
For the return trip, the speed was 10 mph faster, so it will be "x + 10" mph.
The distance covered in the return trip is 6 hours * (x + 10) mph = 6(x + 10) miles.
Since the distance traveled is the same for both trips (going and returning), we can set up an equation:
7x = 6(x + 10).
Now let's solve the equation to find the value of "x":
7x = 6x + 60
7x - 6x = 60
x = 60
Therefore, the consultant's speed on the initial trip was 60 mph, and the speed on the return trip was 60 + 10 = 70 mph.