Questions LLC
Login
or
Sign Up
Ask a New Question
Science
Chemistry
What is the equilibrium concentration of ammonium ion in a 0.77 M solution of ammonia (NH3, Kb = 1.8 ´ 10–5) at 25oC?
1 answer
Answered below.
You can
ask a new question
or
answer this question
.
Similar Questions
What is the equilibrium concentration of ammonium ion in a 0.77 M solution of ammonia (NH3, Kb = 1.8 ´ 10–5) at 25oC?
Top answer:
NH3 + HOH ==> NH4^+ + OH^- Set up an ICE chart, plug into the Kb expression for NH3 and solve. Post
Read more.
The metal ion M2+ in ammonia, NH3 forms the complex ion M(NH3)62+ (Kf = 5.1x108). Calculate the M2+ concentration when the
Top answer:
See your post below with the MX and NaCN
Read more.
The metal ion M2+ in ammonia, NH3 forms the complex ion M(NH3)62+ (Kf = 5.1x108). Calculate the M2+ concentration when the
Top answer:
M^2+ + 6NH3 ==> [M(NH3)6]^2+ Write the Kf expression for the above reaction, plug in the equilibrium
Read more.
The metal ion M2+ in ammonia, NH3 forms the complex ion M(NH3)62+ (Kf = 5.1x108). Calculate the M2+ concentration when the
Top answer:
To solve this problem, we need to use the equilibrium constant expression and the provided
Read more.
Suppose that 2.25 grams of CuSO4 are dissolved in 930 mLs of 0.30 M ammonia. What concentration (Molarity) of Cu2+ ion is
Top answer:
To determine the concentration of Cu2+ ion that is free in the aqueous solution, we can use the
Read more.
Please help!!! I need the answers ASAP I have 40 mins to pass this
A 0.800 M solution of NH3 is prepared and is in equilibrium
Top answer:
To solve these questions, you'll need to use some basic chemistry principles and formulas. I'll
Read more.
Hydrogen chloride is added to a buffer solution of ammonia, NH3, and ammonium chloride, NH4Cl. What is the effect on the
Top answer:
doop doop
Read more.
In a qualitative analysis, the test for the presence of Cu^2+ ion is the formation of the bright blue complex ion Cu(NH3)42+.
Top answer:
(NH3) = 15 x 1/2 = 7.5M (Cu^2+)= 0.200 x 1/2 = 0.100 .....Cu^2+ + 4NH3 ==> [Cu(NH3)4]^2+
Read more.
Ammonia (NH3) ionizes according to the following reaction:
NH3(aq) + H2O(l) ⇌ NH4+(aq) + OH–(aq) The base dissociation
Top answer:
I answered this for you below. I may be able to help if you tell me what you don't understand but
Read more.
Ammonia (NH3) ionizes according to the following reaction:
NH3(aq) + H2O(l) ⇌ NH4+(aq) + OH–(aq) The base dissociation
Top answer:
That looks ok to me.
Read more.
Related Questions
Ammonium iodide dissociates reversibly to ammonia and hydrogen iodide:
NH4I(s) ↔ NH3(g) + HI(g) At 400ºC, Kp = 0.215. If 150 g
The question is: what is the ratio [NH3/[NH4+] in an ammonia/ammonium chloride buffer solution with pH= 10.00? (pKa for
Given the equilibrium:
3H2(g) + N2(g) ⇌ 2 NH3(g) Δ H < 0 How will the equilibrium shift if the concentration of ammonia is
Concentrated aqueous ammonia contains 1.00 mol NH3 dissolved in 2.44 mol H20. What is the mole fraction of NH3 in concentrated
A 0.130-mole quantity of CoCl2 is added to a liter of 1.20 M NH3 solution. What is the concentration of Co2 ions at equilibrium?
What concentration of ammonia, [NH3], should be present in a solution with [NH4+]= 0.734M to produce a buffer solution with pH=
A 0.170-mole quantity of NiCl2 is added to a liter of 1.20 M NH3 solution. What is the concentration of Ni2 ions at equilibrium?
Calculate the molar concentration of uncomplexed Zn2+ (aq) in a solution that contains 0.22 mol of Zn(NH3)4 2+ per liter and
A sample of ammonia gas was allowed to come to equilibrium at 400 K.
2NH3(g) --> N2(g) + 3H2(g) At equilibrium, it was found that
Ammonium iodide dissociates reversibly to ammonia and hydrogen iodide.
NH4I(s) <==> NH3(g) + HI(g) At 400°C, Kp = 0.215.
