Solve:
2^x-3= 32^x+1
32=2^5
2^(x-3)=2^(5x+5)
x-3=5x+5
take if from there.
Do not know how to evaluate:
e^e
To solve the equation 2^x - 3 = 32^(x + 1), we can start by simplifying the expression on the right side of the equation.
32^(x + 1) can be written as (2^5)^(x + 1), because 32 is equal to 2^5.
Using the exponent rule (a^m)^n = a^(m*n), we can simplify it further to 2^(5*(x + 1)) = 2^(5x + 5).
So, the equation becomes 2^x - 3 = 2^(5x + 5).
Now, since the bases on both sides of the equation are the same (2), we can equate the exponents and solve for x.
x = 5x + 5
Subtract 5x from both sides of the equation:
x - 5x = 5
-4x = 5
Divide both sides by -4:
x = 5/-4
Therefore, the solution to the equation is x = -5/4 or -1.25.