The perimiter of a rectangle is 150 inches. The length exceeds the width by 29 inches. Find the length and width.
You have to make an equation and plug in the information based off what you are given.
Perimeter= 2(W)+2(L) [1st equation]
and they told us the Length= 29+w [2nd equation]
so plug that into the first equation
P=2W+2(29+W)
150=2W+2(29+W)
solve for W(width) then plug that answer into the second equation to get the L(length)
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To solve this problem, we can use the information given about the perimeter of the rectangle and the relationship between the length and width.
Let's assume that the width of the rectangle is represented by the variable "w" (in inches).
According to the given information, the length of the rectangle exceeds the width by 29 inches. So, we can represent the length as "w + 29" (in inches).
The formula to calculate the perimeter of a rectangle is: P = 2(length + width).
Substituting the values into the formula, we have:
150 = 2((w + 29) + w)
Now, we can solve this equation to find the width (w) and then use it to find the length (w + 29).
Expanding the equation, we get:
150 = 2(2w + 29)
150 = 4w + 58
Subtracting 58 from both sides of the equation:
150 - 58 = 4w
92 = 4w
Dividing both sides of the equation by 4:
w = 23
The width of the rectangle is 23 inches.
Substituting this value back into the equation, we can find the length:
length = w + 29
length = 23 + 29
length = 52
So, the length of the rectangle is 52 inches.
Therefore, the width of the rectangle is 23 inches, and the length is 52 inches.