Following are three sets of letters. Draw one letter from Set 1 and place it in Set 2. Then draw one
letter from Set 2 and place it in Set 3. Finally, draw a letter from Set 3. What is the probability that
the last letter drawn is a B?
B C B B B B
Set 1 Set 2 Set 3
Assuming set 1 = BC, set 2 = BB and Set 3 = BB, from the data given, I would say the probability is 1.00.
To find the probability of drawing a B as the last letter, we need to determine the number of favorable outcomes (the number of ways to get a B) and the number of possible outcomes.
Set 1: B
Set 2: C
Set 3: B B B B B B
To solve the problem, we can write out all the possible orderings of the letters in Sets 1, 2, and 3 and count how many of them end in a B.
Set 1 -> Set 3: B, B, B, B, B, B (6 orderings)
Set 1 -> Set 2 -> Set 3: B C B, B B B, B B B, B B B, B B B (5 orderings)
Total number of orderings ending in B: 6 + 5 = 11
The number of possible outcomes is the total number of orderings, which is the product of the sizes of Set 1, Set 2, and Set 3: 1 x 2 x 6 = 12.
Therefore, the probability of drawing a B as the last letter is 11/12.