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Mathematics
Algebra
Equations/Graphing
which of the following sets gives the x coordinates where the parabola y=x^2+4X-50 and the line y=7x-10 intersect when drawn in the coordinate plane
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which of the following sets gives the x coordinates where the parabola y=x^2+4X-50 and the line y=7x-10 intersect when drawn in
Top answer:
7x-10 = x^2 + 4 x - 50 x^2 -3x -40 = 0 (x-8)(x+5) = 0 x = 8 or x = -5 (-5,-45) (8,46)
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14) Consider the parabola with equation y = x^2 - 6x + 5.
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You are probably expected to use "completing the square", although other methods are just as
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The vertex of a parabola represented by f(x)=x^2-4x+3 has coordinates of (2,-1). Find the coordinates of the vertex of the
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yes, the new vertex will be (4,-1) proof: f(x-2) = (x-2)^2 - 4(x-2) + 3 = x^2 - 4x + 4 - 4x + 8 + 3
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consider the line y=6x-k and the parabola y=x^2
i) for what value of k is the line y=6x-k a tangent to the parabola y=x^2 ? ii)
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i. at x=3, the slope of the parabola is 6, so at 3, the parabola has a y value of 9, which means if
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Find the coordinates at which the parabola intersects the line y = 2x + 3
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To find the coordinates at which the parabola intersects the line y = 2x + 3, we need to set the
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graph the parabola y=2x^2-6x-3. plot point on the parabola A[1,-7] and draw a line through A with an angle of inclination equal
Top answer:
Just take this one step at a time: a line with inclination 30° has slope tan30° = 1/√3 Now we
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Using the graph, determine the coordinates of the y-intercept of the parabola.
The line crosses across x = -7 and x = -1 and y =
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Without a graph or equation, it is not possible to determine the coordinates of the y-intercept of
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Using the graph, determine the coordinates of the y-intercept of the parabola.\
The line crosses x = 1 and x = 3 and y = -3.
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Without the graph or any specific information, it is not possible to determine the coordinates of
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Find the coordinates of the points of intersection of the straight line y = 3x - 6 with the parabola y = x^2 - 6x + 8 and solve
Top answer:
to solve algebraically, just solve 3x-6 = x^2-6x+8 x^2-9x+14 = 0 (x-7)(x+2) = 0 The graphical
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A parabola F intercepts the x-axis at B and C and y-axis at E
The axis of symmetry of the parabola has equation of x=3. The line
Top answer:
since the axis of symmetry is x=3, y = a(x-3)^2 + k since the line through C and E passes through
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