What is the current produced by a 9-volt battery flowing through a resistance of 2 x 10^-4 ohms?

45000

To calculate the current produced by a 9-volt battery flowing through a resistance of 2 x 10^-4 ohms, you can apply Ohm's Law. Ohm's Law states that the current (I) flowing through a conductor is equal to the voltage (V) divided by the resistance (R).

So, the formula is:

I = V / R

Given that the voltage (V) is 9 volts and the resistance (R) is 2 x 10^-4 ohms, we can substitute these values into the formula and solve for the current (I).

I = 9 V / (2 x 10^-4 ohms)

Next, we need to simplify the expression. To divide by a number in scientific notation, you can multiply the denominator and numerator by the reciprocal of that number.

I = 9 V * (1 / (2 x 10^-4 ohms))

I = 9 V * (1 / (2 x (1 x 10^-4) ohms))

I = 9 V * (1 / (2 x 0.0001 ohms))

I = 9 V * (1 / 0.0002 ohms)

I = 9 V / 0.0002 ohms

Now, we can divide 9 volts by 0.0002 ohms to get the current (I).

I = 9 V / 0.0002 ohms

I ≈ 45,000 Amperes

Therefore, the current produced by a 9-volt battery flowing through a resistance of 2 x 10^-4 ohms is approximately 45,000 Amperes.

To calculate the current produced by a 9-volt battery flowing through a resistance of 2 x 10^-4 ohms, you can use Ohm's Law. Ohm's Law states that the current flowing through a conductor is equal to the voltage applied across it divided by the resistance.

Here's how you can calculate it:

Step 1: Write down the given values:
Voltage (V) = 9 volts
Resistance (R) = 2 x 10^-4 ohms

Step 2: Apply Ohm's Law formula:
Current (I) = V / R

Step 3: Substitute the given values into the formula:
Current (I) = 9 volts / 2 x 10^-4 ohms

Now let's simplify the calculation:

First, we need to convert 10^-4 ohms to a regular decimal form. 10^-4 is equivalent to 0.0001. So, the resistance is 2 x 0.0001 ohms, which equals 0.0002 ohms.

Now we can continue the calculation:

Current (I) = 9 volts / 0.0002 ohms
= 45,000 amperes

Therefore, the current produced by a 9-volt battery flowing through a resistance of 2 x 10^-4 ohms is 45,000 amperes.

Use Ohm's law, again.

This time, in the form
I = V/R

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