Write the equation of the line that passes through point(-6,14)with a slope of -3.
show the work
y-14=-3(x+6)
y-14=-3x-18
y=-3x-4
thanks I had it right
y=4x2-9x+5 separate the values with a comma. round if necessary to the nearest hundredth
To find the equation of a line that passes through a given point and has a given slope, you can use the point-slope form of a linear equation, which is:
(y - y₁) = m(x - x₁)
Where:
- (x₁, y₁) represents the coordinates of the given point on the line.
- m represents the slope of the line.
In this case, the given point is (-6, 14) and the slope is -3. Assigning the values to the equation, we get:
(y - 14) = -3(x - (-6))
(y - 14) = -3(x + 6)
Next, simplify the equation:
(y - 14) = -3x - 18
Now, isolate y by adding 14 to both sides:
y = -3x - 18 + 14
y = -3x - 4
Therefore, the equation of the line that passes through the point (-6, 14) with a slope of -3 is y = -3x - 4.