a) The element with the greatest density is osmium, which has a density of 22.6g/cm3. calculate the mass of 32.1 cm3 of osmium.
Answer: 22.6g x 32.1 = 725.46
Did I have right answer?
b) A team of students determined the density of a sample of wood to be 0.52g/cm3. A handbook of chemistry reported the density of 0.548g/cm3 for the same type of wood. what is the percent error of the students value?
anser:(0.548 - 0.52) / 0.548 x 100 = 5.1%
Can someone check my answer for me?
B is ok.
A is exactly correct; however, you have too many significant figures in the answer. You are allowed only 3 (both 32.1 and 22.6 have three); therefore, you are allowed just 3. Thus, I would round the answer to 725 AND I would put a unit on it of "grams."
a) mass 32.1 / density 22.6 = volume answer: 1.42g volume
a) To calculate the mass of 32.1 cm3 of osmium, you need to multiply the density of osmium (22.6 g/cm3) by the volume (32.1 cm3). So the calculation is:
Mass = Density x Volume
Mass = 22.6 g/cm3 x 32.1 cm3
Now, you can perform the calculation:
Mass = 725.46 g
So, your answer of 725.46 g is correct.
b) To find the percent error of the students' value for density, you need to use the formula:
Percent Error = |(Measured Value - Actual Value) / Actual Value| x 100
In this case, the measured value is 0.52 g/cm3 and the actual value is 0.548 g/cm3, as reported in the handbook. So the calculation is:
Percent Error = |(0.52 g/cm3 - 0.548 g/cm3) / 0.548 g/cm3| x 100
Now, you can perform the calculation:
Percent Error = 5.1%
So, your answer of 5.1% is correct.