A painter needs to cover a triangular region 62 meters by 66 meters by 71 meters. A can of paint covers 70 square meters. How many cans will be needed?
Carson needs to purchase 5.6 meters of tape for a project. If each roll of tape contains 80 cm and costs 5,what is the total cost of the tape that carson must bu
To find out how many cans of paint the painter needs, we first need to calculate the area of the triangular region.
Since the triangular region is not a regular triangle and we do not have its height, we need to use Heron's formula to calculate its area.
Heron's formula states that the area (A) of a triangle with sides a, b, and c is given by:
A = √(s(s-a)(s-b)(s-c))
where s is half of the triangle's perimeter:
s = (a + b + c) / 2
Now let's calculate the area of the triangular region using Heron's formula:
s = (62 + 66 + 71) / 2
s = 99.5
A = √(99.5(99.5-62)(99.5-66)(99.5-71))
A = √(99.5(37.5)(33.5)(28.5))
A ≈ 1482.22 square meters
Since each can of paint covers 70 square meters, we divide the total area of the triangular region by the coverage of one can to find the number of cans needed:
Number of cans = 1482.22 / 70
Number of cans ≈ 21.17
Therefore, the painter will need approximately 22 cans of paint to cover the triangular region.