2NaIO3+5NaHSO3reacts and give 3NaHSO4+2Na2SO4+H2O+I2.
If you wish to prepare 1.00kg of I2, what mass of NaIO3 is required? what mass of NaHSO3?
figure the moles of I2 represented by a mass of 1kg. Then, looking at the coefficents, you must need twice that number of moles of NaIO3. Convert that to mass.
To determine the mass of NaIO3 required to produce 1.00 kg of I2 and the mass of NaHSO3 needed, we can use stoichiometry and the given balanced chemical equation:
2 NaIO3 + 5 NaHSO3 -> 3 NaHSO4 + 2 Na2SO4 + H2O + I2
Let's calculate the mass of NaIO3 first:
Step 1: Determine the molar mass of I2
The molar mass of I2 is approximately 253.8 g/mol.
Step 2: Calculate the number of moles of I2 needed
Since the molar mass of I2 is 253.8 g/mol, the number of moles of I2 required can be calculated using the formula:
moles of I2 = mass of I2 / molar mass of I2
Given that you want to prepare 1.00 kg of I2, we need to convert the mass to grams:
mass of I2 = 1.00 kg × 1000 g/kg = 1000 g
Using the formula, we can calculate the moles of I2 needed:
moles of I2 = 1000 g / 253.8 g/mol ≈ 3.94 moles
Step 3: Use the stoichiometry to find the moles of NaIO3 required
From the balanced chemical equation, we know that 2 moles of NaIO3 react to produce 1 mole of I2. Therefore, the ratio of moles of NaIO3 to moles of I2 is 2:1.
moles of NaIO3 = 3.94 moles I2 × (2 moles NaIO3 / 1 mole I2) = 7.88 moles NaIO3
Step 4: Calculate the mass of NaIO3 needed
Now that we have the number of moles, we can calculate the mass of NaIO3 using the formula:
mass of NaIO3 = moles of NaIO3 × molar mass of NaIO3
The molar mass of NaIO3 is approximately 197.9 g/mol.
mass of NaIO3 = 7.88 moles × 197.9 g/mol ≈ 1559.35 g ≈ 1.56 kg
Therefore, approximately 1.56 kg of NaIO3 is required to produce 1.00 kg of I2.
Let's now calculate the mass of NaHSO3 needed:
Step 1: Use the stoichiometry to find the moles of NaHSO3 required
From the balanced chemical equation, we know that 5 moles of NaHSO3 react to produce 1 mole of I2. Therefore, the ratio of moles of NaHSO3 to moles of I2 is 5:1.
moles of NaHSO3 = 3.94 moles I2 × (5 moles NaHSO3 / 1 mole I2) = 19.7 moles NaHSO3
Step 2: Calculate the mass of NaHSO3 needed
Now that we have the number of moles, we can calculate the mass of NaHSO3 using the formula:
mass of NaHSO3 = moles of NaHSO3 × molar mass of NaHSO3
The molar mass of NaHSO3 is approximately 104.1 g/mol.
mass of NaHSO3 = 19.7 moles × 104.1 g/mol ≈ 2051.77 g ≈ 2.05 kg
Therefore, approximately 2.05 kg of NaHSO3 is required to produce 1.00 kg of I2.