A shot-putter moves his arm and the 7.0 kg shot through a distance of 1 meters iving the shot a velocity of 10 m/s from rest. Find the average force exerted on the shot during this time
how do you solve this problem.
Is this question related to Kinetic Energy formulas
force*time= mass*changevelocity
time= 1m/avgvelocity= 1/5 sec
Yes, this question is related to calculating the average force exerted on an object. To find the average force, you can use the equation:
Average force = Mass × (Change in velocity / Time)
In this case, the mass of the shot is given as 7.0 kg, and the change in velocity is from rest to 10 m/s. We need to find the time it takes for this change in velocity.
To find the time, we can use the formula:
Final velocity = Initial velocity + (Acceleration × Time)
In this case, the initial velocity is 0 m/s, the final velocity is 10 m/s, and we need to find the acceleration.
Since the shot-putter moves his arm through a distance of 1 meter, we can use the equation:
Distance = Initial velocity × Time + (0.5 × Acceleration × Time^2)
Since the initial velocity is 0 m/s, this simplifies to:
Distance = 0.5 × Acceleration × Time^2
Plugging in the given distance as 1 meter, we can solve for time with the given acceleration.
Once we have the time, we can then calculate the average force exerted on the shot using the first equation.
Yes, this question is related to the concepts of work, energy, and kinetic energy. To solve this problem, we will use the work-energy theorem.
The work done on an object is given by the equation:
Work = Force * Distance * cos(theta)
where theta is the angle between the direction of the force and the direction of motion. In this case, the force applied is along the direction of motion, so theta is 0 degrees and the cos(theta) is equal to 1.
The work done on the shot is equal to the change in its kinetic energy, which can be calculated using the formula:
Kinetic Energy = (1/2) * mass * velocity^2
Given:
Mass (m) = 7.0 kg
Distance (d) = 1 meter
Initial velocity (u) = 0 m/s
Final velocity (v) = 10 m/s
First, let's find the change in kinetic energy:
Change in kinetic energy = (1/2) * m * (v^2 - u^2)
= (1/2) * 7.0 kg * (10^2 - 0^2)
= 350 J
Next, since the work done is equal to the change in kinetic energy, we have:
Work = Change in kinetic energy
= 350 J
Finally, we can find the average force exerted on the shot by rearranging the work formula:
Average Force = Work / Distance
= 350 J / 1 meter
= 350 N
Therefore, the average force exerted on the shot during this time is 350 Newtons.