Can someone show me the structural formula (lewis diagram) for ethene???
Please
H H
\ /
C=C
/ \
H H
Ugh. Move the last pair of H over to the second C
H
..
C:H
..
..
C:H
..
H
Sure! To determine the structural formula or Lewis diagram for ethene (C2H4), we need to consider the valence electrons of each atom.
1. Start by counting the total number of valence electrons for both carbon (C) and hydrogen (H). Carbon is in group 14, so it has 4 valence electrons, and there are 2 carbon atoms in ethene. Hydrogen is in group 1, so it has 1 valence electron, and there are 4 hydrogen atoms in ethene.
2. The total number of valence electrons in ethene is (4 valence electrons × 2 carbon atoms) + (1 valence electron × 4 hydrogen atoms) = 8 + 4 = 12 valence electrons.
3. Connect the two carbon atoms together with a double bond. A double bond consists of a sigma bond (formed by overlapping of atomic orbitals in the inter-nuclear region) and a pi bond (formed by the side-to-side overlap of atomic orbitals parallel to the internuclear axis). This double bond is represented by a double line between the carbon atoms.
4. Distribute the remaining valence electrons around the atoms to satisfy the octet rule (except for hydrogen, which only needs 2 valence electrons). Place 3 lone pairs of electrons around each carbon atom and one hydrogen atom bonded to each carbon atom.
5. Check to ensure that the carbon and hydrogen atoms have achieved an octet of electrons (except for hydrogen) and that the total number of valence electrons matches the original count.
The structural formula or Lewis diagram for ethene (C2H4) is:
H H
\ /
C=C
| |
H H
I hope this helps! Let me know if you have any other questions.