Calculate the solubility in grams per 100 ml of water of potassium sulfate if 1.20 g of the solid dissolves in 10.5 mL of water at 20*C
1.2 x (100/10.5) = ??
Ah, so you're looking for the solubility of potassium sulfate? Well, let's clown around with some calculations then!
First, we need to convert the volume from milliliters to liters. So, 10.5 mL becomes 0.0105 L.
Now, we can calculate the solubility in grams per liter (g/L). We divide the mass of the solid (1.20 g) by the volume in liters (0.0105 L) to get the solubility in grams per liter.
1.20 g / 0.0105 L = 114.29 g/L
Lastly, we want to express the solubility in grams per 100 mL of water. Since 100 mL is 0.1 L, we can use a simple clownish proportion to convert the solubility from grams per liter to grams per 100 mL.
114.29 g/L * 0.1 L / 1 L = 11.43 g/100 mL
So, the solubility of potassium sulfate in water at 20°C is approximately 11.43 grams per 100 mL. Remember, this calculation is just a clownish approximation, so treat it with a little bit of laughter!
To calculate the solubility of potassium sulfate in grams per 100 ml of water, we need to use the given values of mass of the solid and volume of water.
Step 1: Convert the volume of water from milliliters (mL) to grams (g):
Density of water = 1 g/mL
Mass of water = Volume of water * Density of water
Mass of water = 10.5 mL * 1 g/mL
Mass of water = 10.5 g
Step 2: Calculate the solubility in grams per 100 ml of water:
Solubility = (Mass of solid / Mass of water) * 100 ml
Solubility = (1.20 g / 10.5 g) * 100 ml
Solubility = 0.114 * 100 ml
Solubility = 11.4 g/100 ml
Therefore, the solubility of potassium sulfate in grams per 100 ml of water is 11.4 g/100 ml.
To calculate the solubility of potassium sulfate in grams per 100 ml of water, we need to use the given information of the amount of solid that dissolved in a specific volume of water.
Step 1: Convert the volume of water from milliliters (mL) to liters (L).
Given: Volume of water = 10.5 mL
Conversion: 10.5 mL = 0.0105 L (since 1 L = 1000 mL)
Step 2: Calculate the solubility in grams per liter (g/L) of water.
Given: Mass of potassium sulfate = 1.20 g
Solubility (g/L) = Mass of solute (g) / Volume of solvent (L)
Solubility = 1.20 g / 0.0105 L = 114.29 g/L
Step 3: Calculate the solubility in grams per 100 ml (grams/100 ml) of water.
Since 1 L = 1000 mL, we can convert the solubility from grams per liter (g/L) to grams per 100 ml (grams/100 ml) using the following conversion:
Solubility (g/100 ml) = Solubility (g/L) * 10
Solubility = 114.29 g/L * 10 = 1142.9 g/100 ml
Therefore, the solubility of potassium sulfate in grams per 100 ml of water at 20°C is 1142.9 g/100 ml.