what is the square root of 9x (to the power of 8)
Explain too?
3x^4
Sq. rt. of 9 = 3
Sq. rt. of exponent = x^(8 * 1/2) = x^4
exponent of 1000
To find the square root of 9x raised to the power of 8, we first need to simplify the expression inside the square root.
We know that the square root of a number raised to an even power is equal to the number itself. Therefore, we can rewrite 9x raised to the power of 8 as (3x)^8.
Now, taking the square root of (3x)^8, we can use the property of exponents that states when raising a power of a power, we multiply the exponents. So, the square root of (3x)^8 is equal to (3x)^(8/2), which simplifies to (3x)^4.
Finally, we can expand (3x)^4 as (3x)(3x)(3x)(3x), which is equal to 81x^4.
To sum up, the square root of 9x^8 is equal to 81x^4.