At what cold-reservoir temperature (in degree C) would a Carnot engine with a hot-reservoir temperature of 350degree C have an efficiency of 70%?
Wouldn't it be solved by...
.7=(H-(350+273))/H ?
To find the cold-reservoir temperature at which a Carnot engine has an efficiency of 70%, we can use the Carnot efficiency formula:
Efficiency = 1 - (Tc/Th)
where Efficiency is given as 70% (or 0.7), Tc is the cold-reservoir temperature, and Th is the hot-reservoir temperature.
Let's rearrange the formula to solve for Tc:
0.7 = 1 - (Tc/350)
First, subtract 0.7 from both sides of the equation:
0.7 - 1 = -Tc/350
Next, simplify:
-0.3 = -Tc/350
To isolate Tc, multiply both sides of the equation by 350:
(-0.3) * 350 = -Tc
Finally, solve for Tc:
Tc = 105
Therefore, the cold-reservoir temperature at which a Carnot engine with a hot-reservoir temperature of 350°C has an efficiency of 70% is 105°C.