Use the quadratic formula to find the x value that will solve the equation 2x^2-3x+10=0
To find the solution for the equation 2x^2-3x+10=0 using the quadratic formula, we need to identify the coefficients a, b, and c in the general quadratic equation form ax^2 + bx + c = 0.
For the given equation:
a = 2
b = -3
c = 10
Now we can apply the quadratic formula, which is:
x = (-b ± √(b^2 - 4ac)) / (2a)
Plugging in the values from our equation:
x = (-( -3) ± √((-3)^2 - 4(2)(10))) / (2(2))
Simplifying further:
x = (3 ± √(9 - 80)) / 4
x = (3 ± √(-71)) / 4
Since the term inside the square root results in a negative value, it means that there are no real solutions to this equation. The graph of the equation 2x^2-3x+10=0 does not intersect the x-axis.