a projectile is fired in the earth's gravitational field with a horizontal velocity of v=9.00 m/s. How far does it go in the horizontal direction in 0.550 seconds?

9.0 m/s * 0.550 s = ___ meters

Not very far.

The horizontal velocity component remains the same during flight.

4.95 m

To find the horizontal distance traveled by a projectile, we can use the formula:

Horizontal distance = velocity × time

Given:
Horizontal velocity (v) = 9.00 m/s
Time (t) = 0.550 seconds

Substituting these values into the formula, we can calculate the horizontal distance:

Horizontal distance = 9.00 m/s × 0.550 seconds

Horizontal distance = 4.95 meters

Therefore, the projectile would travel 4.95 meters in the horizontal direction in 0.550 seconds.

To find the horizontal distance traveled by the projectile in a given time, you can use the formula:

Horizontal distance = horizontal velocity × time

In this formula, the horizontal velocity is given as 9.00 m/s, and the time is given as 0.550 seconds. So, we can substitute these values into the formula to find the horizontal distance:

Horizontal distance = 9.00 m/s × 0.550 s

Now, let's calculate the answer:

Horizontal distance = 4.95 meters

Therefore, the projectile travels a horizontal distance of 4.95 meters in 0.550 seconds.