Train A and B are traveling in the same direction on parallel tracks. Train A is traveling at 100 miles per hour and train B is traveling at 120 miles per hour. Train A passes a station at 5:20am. If train B passes the same station at 5:35 am, at what time will train B catch up to train A?
Train B would catch up to train A at 7:07am? is this correct
distance apart at station =100mph*1/4hr
relative velocity= distance/time
time= 25mi/20mph=5/4 hr Add that to 5:35
6:20 am
tickets for a school sell for $8 for floor seats and $6 for balcony seats. For one performance 72 tickets were sold, bringing in $516. how many tickets were sold
To find the time when train B catches up to train A, we need to determine the time difference between when train A passes the station and when train B passes the station.
Given that train A passed the station at 5:20am and train B passed the station at 5:35am, the time difference is 5:35am - 5:20am, which is 15 minutes.
Now, we need to calculate the distance that train A travels in that time period. Since train A is traveling at a speed of 100 miles per hour, we can convert the 15 minutes into hours by dividing it by 60: 15/60 = 0.25 hours.
The distance traveled by train A in 0.25 hours is 100 miles per hour * 0.25 hours = 25 miles.
Therefore, train B needs to catch up to train A by covering a distance of 25 miles.
The relative speed between train A and train B is the difference between their speeds, which is 120 miles per hour - 100 miles per hour = 20 miles per hour.
Using the formula time = distance / speed, we can calculate the time it takes for train B to catch up to train A: time = 25 miles / 20 miles per hour = 1.25 hours.
Now, we need to add this time to the time train B passed the station (5:35am) to find the time when train B catches up to train A:
5:35am + 1 hour + 0.25 hours = 6:35am + 0.25 hours = 6:35am + 15 minutes = 6:50am.
Therefore, the correct time when train B catches up to train A is 6:50am, not 7:07am.