What volume of 0.200 M Fe(NO3)3 is needed to make 50ml of o.oo200M Fe(NO3)3?
mL x M = mL x M
csd
To answer this question, we need to use the concept of dilution. The formula for dilution is:
C1V1 = C2V2
where C1 represents the initial concentration, V1 represents the initial volume, C2 represents the final concentration, and V2 represents the final volume.
In this case:
C1 = 0.200 M (initial concentration)
V1 = ?
C2 = 0.00200 M (final concentration)
V2 = 50 mL (final volume)
Now, let's solve for V1 using the formula:
C1V1 = C2V2
(0.200 M) V1 = (0.00200 M) (50 mL)
V1 = (0.00200 M) (50 mL) / (0.200 M)
V1 = 0.100 mL
Therefore, to make a 0.00200 M Fe(NO3)3 solution, you only need to dilute 0.100 mL of 0.200 M Fe(NO3)3 with enough solvent to reach a final volume of 50 mL.