a cannon with a mass of 1,500kg fired a 7kg cannonball along its 3m long barrel in 0.015 seconds a)calculate the acceleration of the cannonball
b)the force acting on the cannonball
c) the reaction force exerted on the cannon
d)the acceleration of the cannon
e) the distance the cannon recoils during the 0.015 seconds
To calculate the answers, we can use Newton's second law of motion, which states that the acceleration of an object is equal to the net force acting on it divided by its mass.
a) Calculate the acceleration of the cannonball:
First, we need to determine the net force acting on the cannonball. This can be done using the equation F = ma, where F is the force, m is the mass, and a is the acceleration.
Given:
Mass of the cannonball (m) = 7 kg
Using Newton's second law, we can calculate the acceleration (a):
a = F/m
b) Calculate the force acting on the cannonball:
Using the calculated acceleration (a) from part a, we can find the force (F) by rearranging the equation as:
F = ma
Next, we need to convert the given time interval from seconds to seconds squared:
Time (t) = 0.015 seconds
c) Calculate the reaction force exerted on the cannon:
According to Newton's third law of motion, for every action, there is an equal and opposite reaction. Therefore, the reaction force exerted on the cannon will be equal in magnitude and opposite in direction to the force acting on the cannonball.
d) Calculate the acceleration of the cannon:
To calculate the acceleration of the cannon, we can use the equation F = ma, where F is the force acting on the cannon, m is the mass of the cannon, and a is the acceleration.
Given:
Mass of the cannon (m) = 1,500 kg
e) Calculate the distance the cannon recoils during the 0.015 seconds:
We can use the formula for distance travelled (d) when the initial velocity (u) and time (t) are known:
d = ut + (1/2)at^2
Given:
Initial velocity (u) = 0 (assuming the cannon is initially at rest)
Now let's solve each part using the given values to find the answers.