A loaf of bread is normally distributed with a mean of 22 ounces and a standard deviation of .5 ounces.
What is the probability that a loaf of bread is <21 ounces?
Use the same method indicated in the previous post.
To find the probability that a loaf of bread is less than 21 ounces, we can use the standard normal distribution table and z-scores.
First, we need to calculate the z-score for 21 ounces. The z-score formula is calculated by subtracting the mean from the value of interest and dividing it by the standard deviation:
z-score = (x - mean) / standard deviation
In this case, the mean is 22 ounces, and the standard deviation is 0.5 ounces. So, the z-score would be:
z-score = (21 - 22) / 0.5 = -1 / 0.5 = -2
Now we need to find the probability associated with this z-score. Looking up the z-score -2 in the standard normal distribution table, we find that it corresponds to a probability of approximately 0.0228.
Therefore, the probability that a loaf of bread is less than 21 ounces is approximately 0.0228, or 2.28%.