A 1.00 L volume of 0.609 M HNO3 is condensed to a volume of 0.750 L, calculate the molarity (M) of H+ in the new solution
To calculate the molarity (M) of H+ in the new solution, we can use the concept of dilution.
Dilution formula:
M1V1 = M2V2
Where:
M1 = initial molarity
V1 = initial volume
M2 = final molarity
V2 = final volume
In this case, our initial solution has a volume of 1.00 L and a molarity of 0.609 M (M1 = 0.609 M, V1 = 1.00 L). After condensation, the volume becomes 0.750 L (V2 = 0.750 L). We need to calculate the final molarity (M2).
Using the dilution formula:
M1V1 = M2V2
Substituting the given values:
(0.609 M)(1.00 L) = M2(0.750 L)
0.609 = M2(0.75)
To get M2 alone, we divide both sides of the equation by 0.75:
M2 = 0.609 / 0.75
Calculating this, we find:
M2 = 0.812 M
Therefore, the molarity (M) of H+ in the new solution is 0.812 M.