A 1.00 L volume of 0.609 M HNO3 is condensed to a volume of 0.750 L, calculate the molarity (M) of H+ in the new solution

To calculate the molarity (M) of H+ in the new solution, we can use the concept of dilution.

Dilution formula:

M1V1 = M2V2

Where:
M1 = initial molarity
V1 = initial volume
M2 = final molarity
V2 = final volume

In this case, our initial solution has a volume of 1.00 L and a molarity of 0.609 M (M1 = 0.609 M, V1 = 1.00 L). After condensation, the volume becomes 0.750 L (V2 = 0.750 L). We need to calculate the final molarity (M2).

Using the dilution formula:

M1V1 = M2V2

Substituting the given values:

(0.609 M)(1.00 L) = M2(0.750 L)

0.609 = M2(0.75)

To get M2 alone, we divide both sides of the equation by 0.75:

M2 = 0.609 / 0.75

Calculating this, we find:

M2 = 0.812 M

Therefore, the molarity (M) of H+ in the new solution is 0.812 M.