A household bleach solution contains 5.25% (by mass) NaClO. How many moles of NaClO are needed to make 1000 L of the solution? (density = 1.07g/mL)
This is the complete question on my assignment. It's 1000 L.
OK. The way I interpret this is that someone wants to make up 1,000 L of a solution that is 5.25% NaClO. If that's the right way I would do this. First I would change the mass percent to molarity or at least to moles/some volume.
5.25mass percent means
5.25 g NaClO/100 g solution. Since the density is 1.07, we can use the density to see what volume that is.
mass = v x d
m/d = v = 100g/1.07 = about 94 mL but you need to go through and do it more accurately.
Then you can determine number of moles in 5.25 g NaClO from moles = grams/molar mass. I get about 0.07 moles; again, you do it more accurately. So you actually have a solution that is about 0.07 moles/0.093 L. You want to make 1,000 L of that. I would simply multiply the ratio like this.'
0.07 moles x 1000L/0.093 L = moles NaClO required.
Actually, I think there is an easier way to do it. Why don't you do both and see if you get the same answer?
Density is 1.07 g/mL so 1000 mL has a mass of 1.07 g/mL x 1000 mL = 1070 grams. How much of that is NaClO. Its
1070 x 0.0525 = about 56 grams
How many moles is that?
56/74 = about 0.76 moles NaClO for 1 L of solution. To make 1000 L you multiply by 1000 to get about 760 moles.
I think the latter may be easier to understand.
Well, it seems like someone wants to do some serious cleaning! But don't worry, I'm here to help you calculate the number of moles needed.
Since we know the percentage of NaClO in the solution, we can easily calculate its mass.
The density of the solution is given as 1.07g/mL. So, for every milliliter (mL) of the solution, we have 1.07 grams (g).
Since we want to make 1000 liters (L) of the solution, we need to convert liters to milliliters. There are 1000 milliliters in one liter. So, 1000 L is equal to 1000 x 1000 mL, which is 1,000,000 mL.
Now that we know the volume and the density, we can calculate the mass of the solution:
Mass = density x volume
Mass = 1.07 g/mL x 1,000,000 mL = 1,070,000 g
Since we know that the NaClO solution is 5.25% sodium hypochlorite (NaClO) by mass, we can calculate the mass of NaClO in the solution:
Mass of NaClO = 5.25% x Mass of solution
Mass of NaClO = 5.25/100 x 1,070,000 g = 56,175 g
Now, we need to convert the mass of NaClO into moles. To do that, we need to know the molar mass of NaClO.
The molar mass of NaClO can be calculated as follows:
Molar mass of NaClO = (molar mass of Na) + (molar mass of Cl) + (molar mass of O)
Molar mass of NaClO = (22.99 g/mol) + (35.45 g/mol) + (16.00 g/mol)
Molar mass of NaClO = 74.44 g/mol
Now we can calculate the number of moles of NaClO:
Moles of NaClO = Mass of NaClO / Molar mass of NaClO
Moles of NaClO = 56,175 g / 74.44 g/mol = 754.03 mol
So, in order to make 1000 L of the solution, you will need approximately 754.03 moles of NaClO. That should be enough to clean up any mess!
To determine the number of moles of NaClO needed to make 1000 L of the household bleach solution, we need to follow these steps:
Step 1: Calculate the mass of the solution.
To do this, we need to multiply the volume (1000 L) by the density of the solution (1.07 g/mL). However, we need to convert the volume from liters to milliliters since the density is given in grams per milliliter.
1000 L = 1000 * 1000 mL/L = 1,000,000 mL
mass of solution = volume * density
mass of solution = 1,000,000 mL * 1.07 g/mL
mass of solution = 1,070,000 g
Step 2: Calculate the mass of NaClO in the solution.
The concentration of NaClO is given as 5.25% (by mass). This means that in 100 grams of the solution, 5.25 grams are NaClO.
mass of NaClO = 5.25% * mass of solution
mass of NaClO = 5.25/100 * 1,070,000 g
mass of NaClO = 56,175 g
Step 3: Calculate the moles of NaClO.
To convert grams of NaClO to moles, we divide the mass (in grams) by the molar mass of NaClO. The molar mass of NaClO is the sum of the atomic masses of sodium (Na), chlorine (Cl), and oxygen (O).
molar mass of NaClO = atomic mass of Na + atomic mass of Cl + 3 * atomic mass of O
molar mass of NaClO = 22.99 g/mol + 35.45 g/mol + 3 * 16.00 g/mol
molar mass of NaClO = 74.44 g/mol
moles of NaClO = mass of NaClO / molar mass of NaClO
moles of NaClO = 56,175 g / 74.44 g/mol
moles of NaClO = 754.91 mol
Therefore, approximately 754.91 moles of NaClO are needed to make 1000 L of the household bleach solution.
To find the number of moles of NaClO needed to make 1000 L of the solution, we need to use the given information about the concentration and the density of the solution.
1. Start by calculating the mass of the solution:
Mass of solution = Volume of solution x Density
Mass of solution = 1000 L x 1.07 g/mL
2. Convert the mass of the solution into grams:
Mass of solution = 1000 L x 1.07 g/mL = 1070 g
3. Determine the mass of NaClO in the solution:
Mass of NaClO = Mass of solution x Concentration of NaClO
Mass of NaClO = 1070 g x 5.25% = 56.175 g
4. Calculate the molar mass of NaClO (sodium hypochlorite):
The molar mass of NaClO can be calculated by summing the atomic mass of each element:
Na (sodium) = 22.99 g/mol
Cl (chlorine) = 35.45 g/mol
O (oxygen) = 16.00 g/mol
Molar mass of NaClO = 22.99 g/mol + 35.45 g/mol + 16.00 g/mol = 74.44 g/mol
5. Convert the mass of NaClO to moles:
Moles of NaClO = Mass of NaClO / Molar mass of NaClO
Moles of NaClO = 56.175 g / 74.44 g/mol
After performing the calculation, the number of moles of NaClO needed to make 1000 L of the solution will be obtained.