A parent’s chance of passing a rare inherited disease on
to a child is 0.15. What is the probability that, in a family
of three children, none of the children inherits the
disease from the parent?
The three probabilities of not getting it are independent so product
(1-.15)^3
about .614
Thank you!
To find the probability that none of the three children inherits the disease from the parent, we need to calculate the probability of each child not inheriting the disease and then multiply them together.
Given that the chance of passing the disease to a child is 0.15, the probability of a child not inheriting the disease is 1 - 0.15 = 0.85.
Let's calculate the probability for each child not inheriting the disease:
Prob(not inheriting) = 0.85
Since we have three children, we multiply the probabilities together:
Prob(none of the children inherit) = (0.85) * (0.85) * (0.85) = 0.614125
Therefore, the probability that none of the children inherits the disease from the parent is approximately 0.6141, or 61.41%.