What is the molality if 82grams of CaNO4 is dissolved in 2000grams of Water?

Check your post. I'm not familiar with anything like CaNO4.

However, this is what you do.
Convert 82 grams to moles. moles = grams/molar mass.
Then mols/2 = molality. The 2 is for 2 kg.

Oh ok thank you i was confused, i mixed molarity with moles i got them backwards. Thank you DrBob222

To find the molality of a solution, you need to know the amount of solute (CaNO4 in this case) and the mass of the solvent (water in this case).

First, calculate the moles of CaNO4 using its molar mass:

Molar mass of CaNO4 = atomic mass of Calcium + atomic mass of Nitrogen + 4 * atomic mass of Oxygen
= (40.08 g/mol) + (14.01 g/mol) + 4 * (16.00 g/mol)
= 164.09 g/mol

Number of moles of CaNO4 = Mass of CaNO4 / Molar mass of CaNO4
= 82 g / 164.09 g/mol
≈ 0.5 moles

Next, calculate the mass of the water in kilograms:

Mass of water = 2000 g = 2 kg

Finally, calculate the molality:

Molality = Moles of solute / Mass of solvent (in kg)
= 0.5 moles / 2 kg
= 0.25 mol/kg

Therefore, the molality of the solution is 0.25 mol/kg.